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ICE
LOAD AND CONCURRENT WIND LOAD
Design
code: ASCE 7-02 & 05
Section
10.4: Ice load due to freezing rain
Important
factors and equations:
1.
ASCE 10.4.1: Ice load shall be determined using the weight of glaze ice form on
all expose surfaces of the structural members
2.
Cross section of ice on structural shape, prismatic members, and other similar
shapes, shall be
Ai
= p
td
(Dc
+ td)
Where
Ai
is cross section of ice, td is thickness of ice, Dc is
equivalent diameter of structural shape as
3.
For large plate, and large three-Dimentional objects such as domes and sphere,
volume of ice shall be determined as
Vi = p
td As
For
flat plate As is flat area of plate.
For
domes and spheres, As = p r2. r is radius of
domes or spheres.
Vi
can be multiply by 0.8 for vertical plate, 0.6 for horizontal plate.
4.
Ice density is 56 lb/ft3 minimum.
5.
Normal ice thickness, t, due to freezing rain at a height of 33 ft and the
concurrent wind speed is determined from Figure 10-2, 10-3, and 10-4 on ASCE
7-02.
6.
Adjustment factor for height is
fz = (z/33)0.1
for 0 to 900 ft., fz = 1.4 for 900 ft and higher.
7.
Important factor is listed in Table 10-1.
8.
Topographic Factor,
Kzt = (1+K1+K2+K3)2
where K1, K2, K3 are determined from
Figure 6-4 of ASCE 7-02.
9.
Design ice thickness is determined
as
td = 2 t Ii
fz (Kzt)0.35
Section
10.5 Wind on ice-covered structures.
Important
factors and equations:
- The
projected area exposed to wind shall be increased by td to all
boundry.
- Wind
load on iced structure shall be based on concurrent wind speed, Vc
from Figures 10-2,10-3, and 10-4 instead of 3 second gust from wind storm in
Section 6.
- Procedure
for calculating wind load is the same as in Section 6.
- Parameters
for calculating wind on ice-covered Chimney, Tanks, and
similar structures are the same as those in Table 6-19 except that DÖqz
shall be used for all round cross section.
- Calculation
of wind on ice-covered solid freestanding walls and solid signs are the same
as those in Table 6-10.
Velociaty pressure, qz = 0,00256 Kz Kzt
Kd Vc2 Ii.
Kd = 0.85 for using load combination, Kd = 1 for
wind along.
Kz = 2.01 (z/zg)2/a
where z is height above ground, z shall not be less than 15
ft. except that z shall not be
less than 30 ft for exposure B for low rise building and for
component and cladding.
a
and zg are taken as follows:
|
Expsoure
|
a
|
zg (ft)
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B
|
7.0
|
1200
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C
|
9.5
|
900
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D
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11.5
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700
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- Parameters
for calculating wind on ice-covered open signs and lattice frameworks are
the same as those in Table 6-21 except that DÖqz
shall be used for all round cross section. The solidity ratio shall be based on the projected area
including ice.
- Parameters
for calculating wind on ice-covered trussed towers are the same as those in
Table 6-22. The solidity ratio
shall be based on the projected area including ice.
Design
Procedure:
- Determine
normal ice thickness and concurrent wind speed from Figure 10-2,10-3, 10-4,
or a site-specific study.
- Determine
topographic factor, Kzt.
- Determine
importance factor, Ii.
- Determine height
factor, fz.
- Determine design ice
thickness, td.
- Determine weight of
ice.
- Determine wind
parameter Kz and Kd.
- Determine velocity
pressure, qz = 0,00256 Kz Kzt Kd
Vc2 Ii.
- Determine force
coefficient, Cf.
- Determine gust effect
factor G.
- Determine wind
pressure, p = qz G Cf.
- Determine wind force, F
= p A, where A is projection area including ice cover.
Design
Examples:
Example 1: A 10 ft diameter
sign logo on the side of 10 story building
Location: New York City, New
York
Design data:
Height above ground: 120 ft
Diameter of logo sign: d = 10
ft
Requirement:
determine weight of ice on the logo and concurrent wind pressure.
Solution:
Design procedure (ASCE 2-02
section 10.7) :
1. Detarmine normal ice
thickness from Figure 10-2: t = 1 in
Determine concurrent wind
speed: Vc = 50 mph
2. Determine topographic
factor from section 10.4.5 (Figure 6.4)
K1 = 0, K2
= 1, K3 = 1
Kzt = (1+K1 K2
K3)2 = 1
3. Determine importance factor
(Table 1.1 & 10.1), Ii = 1
4. Determine height factor
from section 10.4.3,
Z = 120 ft, fz = (Z/33)0.1 =
1.14
5. Determine ice thickness at
roof from section 10.4.6
td = 2.0 t Ii
fz Kzt 0.35 = 2.28 in
6. Determine weight of ice
from section 10.4.1
Area of ice of logo, Af = p d2/4
= 78.5 ft2
Weight of ice, Wsi = Af td x 56 pcf = 834 lb
7. Determine velocity pressure
Kd = 0.85, I = 1
Exposure B, exposure
coefficient
a
= 9.5, Zg = 900 ft, Z = 120 ft
Kz = 2.01 (Z/Zg) 2/a = 1.32
8. Determine velocity pressure
qz = 0.00256 Kz
Kzt Kd (Vc)2 I = 7.2 psf
9. Determine wind force
coefficient (Table 6.21)
Cf = 1.4
10. Gust effect factor
(Section. 6.5.8)
G = 0.85
11. Determine design wind
pressure with ice load
p = qz G Cf = 8.5 psf
12. Concurrent wind force on
logo
A = p
(d + 2 td)2/4 = 84.6 ft2.
F = p A = 720.3 lbs
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